When finding derivatives, it becomes tedious to continually derive the function to find further derivatives. Although I'm not sure of the application of derivatives past the second, I came up with a formula for multiple derivations of polynomials. To do this I observed the way each part of a term changes over each differentiation.
Each time a new derivative is found, the coefficient is multiplied by the power. Thus:
C1 = C0.n(n - 1)(n - 2) ... (n - r) for all n > r
= C0.nPr
= C0.nPr
where C0 is the original coefficient, n gives the original power of x, and r gives the derivative to be found (e.g. For f'''(x), r = 3)
Each time a derivative is found, the constant term is lost. Thus:
C1 = 0, for all 0 < n < r
For negative indices, the sign of the coefficient depends on whether r is odd or even. The magnitude of the coefficient (absolute value) is multiplied by a larger number each time a new derivative is found. Therefore, beginning multiplication at the original power will give the new coefficient as follows:
C1 = C0.(-1)r.|n - r + 1|! / |n + 1|!, for all n < 0
As the powers are simply lessened, in magnitude, by 1 for each derivative, and those for which n is positive and less than r should be eliminated, they are given by:
n1 = n0 - r, for all n0 > r
C1 = C0.(-1)r.|n - r + 1|! / |n + 1|!, for all n < 0
As the powers are simply lessened, in magnitude, by 1 for each derivative, and those for which n is positive and less than r should be eliminated, they are given by:
n1 = n0 - r, for all n0 > r
n1 = 0, for all 0 < n0 < r (as x0 = 1, and the coefficient is 0, thus term is 0 x 1 = 0)
n1 = n0 + r, for all n0 < 0
Collating these results gives a way of finding a term in the derivative of a polynomial function:
Where Tk = C.xn for a polynomial function f(x). tk in the rth derivative of f(x) is given by:
Where Tk = C.xn for a polynomial function f(x). tk in the rth derivative of f(x) is given by:
tk = C.nPrxn - r, for all n > r
tk = 0, for all 0 < n < r
tk = C.(-1)r.|n - r + 1|! / |n + 1|!.xn + r, for all n < 0
tk = 0, for all 0 < n < r
tk = C.(-1)r.|n - r + 1|! / |n + 1|!.xn + r, for all n < 0
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