Recently in 2 Unit Maths we have looked at some special limits involving Trig Ratios. Although these are quite simple to evaluate, I have proven a result that could potentially make the process a lot easier. To cut a long story short, halfway through the exercise in the text book I came up with this:
lim asinbx = lim (c .asinbx).ab
lim asinbx = lim (c .asinbx).ab
x>0 cx x>0 (ab cx ) c
= lim (sinbx).ab
= lim (sinbx).ab
x>0 ( bx ) c
= 1x (ab/c)
= ab/c
So, we can simply take the product of the two constants on the top and divide by the constant on the bottom!
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